Answer:
Step-by-step explanation:
The linear terms are those that are multiplied together to give a quadratic.
It looks like they are (x + 3)(x - 1/2) = y These come from the roots as seen on the graph
The more general equation might be (x + 3)(2x - 1)
The y intersect is determined by letting x = 0
y_int = (0 + 3)(2*0 - 1)
y_int = 3 (-1)
y_int = -3
The point is (0,-3)
One more value should be tried.
Let x = 1
f(x) = (x + 3)(2x - 1)
f(1) = (1 + 3)(2*1 - 1)
f(1) = (4 ) * (2 - 1)
f(1) = 4 * 1
f(1) = 4
I went to all this just to show that a in the general quadratic = 1
y = a(x + 3)(2x - 1)
a calculates out to 1.
