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➷The answer is True.

You can eyeball the triangle or also get a protractor and also see that this is a right triangle. Remember, right triangles have a right angle.

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DOGE

Answer:

ΔFGH is right triangle

Step-by-step explanation:

Given a triangle with dimensions 10, 7, [tex]\sqrt{51}[/tex]

we have to find FGH is right triangle or not.

[tex]Hypotenuse=10 units[/tex]

[tex]Base=7 units[/tex]

[tex]Height=\sqrt{51}[/tex]

If ΔFGH is right triangle, then by Pythagoras theorem

[tex](Hypotenuse)^2=(base)^2+(height)^2\text{ must be satisfied}[/tex]

[tex]FG^2=GH^2+FH^2[/tex]

[tex]10^2=(\sqrt{51})^2+7^2[/tex]

[tex]100=51+49[/tex]

[tex]100=100[/tex]

which is true

Hence, ΔFGH is right triangle

The answer is True