Answer:
The perimeter of both figures is equal to [tex]64\ units[/tex]
Step-by-step explanation:
step 1
we know that
The perimeter of a square is equal to
[tex]P=4b[/tex]
where
b is the side length of the square
we have
[tex]b=8x\ units[/tex]
substitute
[tex]P=4(8x)=32x\ units[/tex]
step 2
we know that
The perimeter of a rectangle is equal to
[tex]P=2(L+W)[/tex]
we have
[tex]L=(5x+8)\ units[/tex]
[tex]W=(14)\ units[/tex]
substitute
[tex]P=2(5x+8+14)=10x+44\ units[/tex]
step 3
Equate both perimeters and solve for x
[tex]10x+44=32x[/tex]
[tex]32x-10x=44[/tex]
[tex]22x=44[/tex]
[tex]x=2\ units[/tex]
step 4
Find the perimeter of both
square
[tex]P=32x=32(2)=64\ units[/tex]
rectangle
[tex]P=10x+44=10(2)+44=64\ units[/tex]