Answer:
The next step is to put all terms into the left side of the equation and group the like trems
Step-by-step explanation:
The first step in determining the solution to the system of equations, [tex]y =-x^2-4x-3[/tex] and [tex]y = 2x + 5[/tex], algebraically is to set the two equations equal as [tex]-x^2-4x-3 = 2x + 5.[/tex]
The next step is to put all terms into the left side of the equation and group the like trems:
[tex]-x^2-4x-3-2x-5=0,\\ \\-x^2+(-4x-2x)+(-3-5)=0,\\ \\-x^2-6x-8=0.[/tex]
Now you can multiply this equation by -1:
[tex]x^2+6x+8=0[/tex]
and solve it using quadratic formula:
[tex]x_{1,2}=\dfrac{-6\pm \sqrt{6^2-4\cdot 8\cdot 1}}{2\cdot 1}=\dfrac{-6\pm\sqrt{4}}{2}=\dfrac{-6\pm 2}{2}=-4,\ -2.[/tex]
