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How many ounces of a 35 %35% alcohol solution must be mixed with 1515 ounces of a 40 %40% alcohol solution to make a 38 %38% alcohol​ solution?

Respuesta :

LammettHash

Let [tex]x[/tex] be the amount of the 35% solution that will be added. The resulting solution will have a total volume of [tex]15+x[/tex], 38% of which is alcohol. 40% of 15 is 6, so the 40% solution contributes 6 oz of alcohol. So

[tex]0.35x+6=0.38(15+x)\implies x=10[/tex]

oz of the 35% solution need to be added.

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