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Problem situation: Anna is at the movie theater and has $35 to spend. She spends $9.50 on a ticket and wants to buy some snacks. Each snack costs $3.50. How many snacks, x, can Anna buy? Inequality that represents this situation: 9.50+3.50x?35 Drag each number to show if it is a solution to both the inequality and the problem situation, to the inequality only, or if it is not a solution. 4 314 912 4.25 ?2 2 Solution to BOTH the inequality and the situation Solution to the inequality ONLY NOT a solution

Respuesta :

calculista

Answer:

The answer in the procedure

Step-by-step explanation:

Let

x-----> the number of snacks

we  know that

The inequality that represent this situation is

[tex]9.50+3.50x\leq 35[/tex]

Solve for x

[tex]3.50x\leq 35-9.50[/tex]

[tex]3.50x\leq 25.50[/tex]

[tex]x\leq 7.3\ snacks[/tex]

The maximum number of snacks is 7

The solution for the inequality is all real numbers less than or equal to 7.3 snacks

The solution for the problem situation is all whole positive numbers less than or equal to 7 snacks

Verify each case

case 1) 4 snacks

Is a solution to both the inequality and the problem situation

case 2) 314 snacks

Is not a solution

case 3) 912 snacks

Is not a solution

case 4) 4.25 snacks

Solution to the inequality ONLY

bxbykarla

Answer:

solution to both: 2,4

solution to inequality ONLY: -2,4.25,3 1/4

NOT a solution: 9 1/2

Step-by-step explanation:

yw ;)