Answer:[tex]3.61(10)^{3} \frac{m}{s^{2}}[/tex]
The centripetal acceleration [tex]a_{c}[/tex] of an object moving in a uniform circular path is given by the following equation:
[tex]a_{c}=\frac{V^{2}}{r}[/tex]
Where:
[tex]V=19m/s[/tex] is the velocity
[tex]r=10cm=0.1m[/tex] is the radius of the circle
[tex]a_{c}=\frac{(19m/s)^{2}}{0.1m}[/tex]
[tex]a_{c}=3610m/s^{2}=3.61(10)^{3}m/s^{2} [/tex]
