Answer: Obtion B
[tex]P = 1.3e ^ {-0.038t}\\\\P = 2.1e ^ {-0.046t}[/tex]
Step-by-step explanation:
The equation for exponential decay has the following form:
[tex]y = pe ^{-rt}[/tex]
Where
p is the initial population
r is the rate of decrease
t is time.
In this problem we have to:
The current population of insect A to be 1.3 million and the current population of insect B to be 2.1 million.
So
[tex]p_1 = 1.3[/tex] in millions
[tex]p_2 = 2.1[/tex] in millions
We also need the populations of insect to be reduced at a rate of 3.8% and insect to be reduced at a rate of 4.6%.
so:
[tex]r_1 = 0.038\\\\r_2 = 0.046[/tex]
then the exponential decay equation for insect A is:
[tex]P = 1.3e ^ {-0.038t}[/tex]
the exponential decay equation for insect B is:
[tex]P = 2.1e ^ {-0.046t}[/tex]
Finally, the system of equations is:
[tex]P = 1.3e ^ {-0.038t}\\\\P = 2.1e ^ {-0.046t}[/tex]
The answer is the Option B