Solution:
It is given that length of a rectangle is 3 more days than than twice its width. The perimeter of the rectangle is 42 centimeters.
So,
Let Required Breadth of Rectangle be x
Now, We have ;
Perimeter of Rectangle = 2(l+b)
Perimeter of Rectangle = 2(2x+3+x)
42 = 2(3x+3)
42 = 6x + 6
42 - 6= 6x
36= 6x
x = 6 cm
Length of Rectangle = 2(6) + 10
Length of Rectangle = 22 cm