Respuesta :

PQ^2=(X2-X1)+(Y2-Y1)^2

PQ^2=(4+3)^2+(25-1)^2

PQ^2=625

PQ=25 unit

The length of the segment PQ is 25 units.

How to find the distance between two points?

  • It can be calculated by using the distance formula.
  • Distance formula consists of the coordinates of points on the graph.

Given: Segment PQ

P = (x₁, y₁) = (-3, 1) and Q = (x₂, y₂) = (4, 25)

We have to find the length of the segment PQ.

Length of the segment PQ can be found by using the distance formula.

⇒ PQ = [tex]\sqrt{(x_2 -x_1)^2+(y_2-y_1)^2}[/tex]

⇒ PQ = [tex]\sqrt{[4-(-3)]^2+(25-1)^2}[/tex]

⇒ PQ = [tex]\sqrt{7^2+24^2}[/tex]

⇒ PQ = [tex]\sqrt{49+576}[/tex]

⇒ PQ = [tex]\sqrt{625}[/tex]

PQ = 25 units

Therefore, the length of the segment PQ is 25 units.

Learn more about the distance between two points here: https://brainly.com/question/24190898

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