tesfayexitlali
contestada

Zn + 2 HCl --> ZnCl2 + H2 How many moles of hydrochloric acid (HCl) are used (assume a complete reaction) if 8.3 moles of zinc chloride (ZnCl) are produced? A 8.3 mol ZnCl2 B None of these answers C 8.3 mol HCl D 4.15 mol HCl E 16.6 mol HCl

Respuesta :

Answer:

E. 16.6 mol HCl

Explanation:

The equation for the reaction is;

Zn + 2 HCl --> ZnCl2 + H2

From the reaction 2 moles of HCl produces 1 mole of ZnCl2

Therefore; 8.3 moles of ZnCl2 will be produced by;

  = 8.3 moles ×2

  = 16.6 Moles of HCl

  Therefore;  E.  16.6 mol HCl

Otras preguntas