Answer:
[tex]4(x+\frac{3}{2})^2+0[/tex]
To solve [tex]ax^2+bx+c=0[/tex] by completing the square:
1. Transform the equation so that the constant term, c , is alone on the right side.
2. If a, the leading coefficient (the coefficient of the [tex]x^2[/tex] term), is not equal to 1, divide both sides by a.
3. Add the square of half the coefficient of the x-term, [tex](\frac{b}{2a})^2[/tex] to both sides of the equation.
4. Factor the left side as the square of a binomial.
5. Take the square root of both sides. (Remember: [tex](x+q)^2[/tex]=r is equivalent to [tex]x+q=+-\sqrt{r}[/tex])
Hope this helps and have a great day!!
