The volume (in mL) required to make 1 L of the solution is 200 mL
Data obtained from the question
- Molarity of stock solution (M₁) = 2 M
- Volume of diluted solution (V₂) = 1 L = 1000 mL
- Molarity of diluted solution (M₂) = 0.4
- Volume of stock solution (V₁) = ?
How to determine the volume of the stock solution
M₁V₁ = M₂V₂
2 × V₁ = 0.4 × 1000
2 × V₁ = 400
Divide both side by 2
V₁ = 400 / 2
V₁ = 200 mL
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