If 20 atoms of aluminum react with 45 molecules of chlorine gas, which reactant is limiting and how many more atoms/molecules would be required to use up all the reactants?

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Eshaunlee476 Eshaunlee476 · Answer 1 · 2016-05-02T18:47:22+02:00

Al:ch2 an molar ratio.

2:3 and an x. X is 30. 20/2 = 10 so an answer is

45/3 = 15. Both ratios are used

45 - 30 = 15 CL2 left.

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Tringa0 Tringa0 · Answer 2 · 2019-06-24T15:11:20+02:00

Explanation:

[tex]2Al+3Cl_2\rightarrow 2AlCl_3[/tex]

According to reaction, 2 atoms of aluminum gas reacts with 3 molecules of chlorine gas.

Then 20 atoms of aluminum will react with :

[tex]\frac{3}{2}\times 20=30 molecules[/tex] of chlorine

Aluminum is a limiting reagent.

Molecules of chlorine left unreacted: 45 - 30 molecules = 15 molecules

Then 15 molecules of chlorine gas will react with :

[tex]\frac{2}{3}\times 15=10 atoms[/tex] of aluminum

10 more atoms of aluminum will required to use up all chlorine.