Respuesta :

imlittlestar

Answer:

x = -2 and y = -3

Step-by-step explanation:

It is given that,

-8x + 3y =7    ----(1)

13x - 3y =-17   -----(2)

To find the value of x and y

eq(1) + eq(2) ⇒

-8x + 3y = 7    ----(1)

13x -  3y = -17   -----(2)

 5x +    = -10

x = -10/5 = -2

Substitute value of x in eq (1)

-8x + 3y =7    ----(1)

-8 * -2  + 3y = 7

16 + 3y = 7

3y = 7 - 16 = -9

y = -9/3 = -3

Therefore x = -2 and y = -3

carlosego

For this case we must solve the following system of equations:

[tex]-8x + 3y = 7\\13x-3y = -17[/tex]

If we add both equations we have:

[tex]-8x + 13x + 3y-3y = 7-17\\5x = -10\\x = \frac {-10} {5}\\x = -2[/tex]

We find the value of the variable "y":

[tex]3y = 7 + 8x\\y = \frac {7 + 8x} {3}\\y = \frac {7 + 8 (-2)} {3}\\y = \frac {7-16} {3}\\y = \frac {-9} {3}\\y = -3[/tex]

Thus, the solution of the system is (-2, -3)

ANswer:

(-2, -3)

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