Answer:
Acceleration, [tex]a=10.4\ m/s^2[/tex]
Explanation:
Given that,
Initial velocity of the ride, u = 0 (at rest)
Final speed of the ride, v = 22.9 m/s
Time taken, t = 2.2 s
Let a is the acceleration of the passengers on this ride. It can be calculated using the formula of the acceleration as :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{22.9-0}{2.2}[/tex]
[tex]a=10.4\ m/s^2[/tex]
So, the time required to bring the car to a stop is [tex]10.4\ m/s^2[/tex]. Hence, this is the required solution.
