Answer:
17.C
18.A
Step-by-step explanation:
17. Slope=(y2-y1)/(x2-x1)
=(-1-(-2))/(4-(-3))
=1/7
18.Slope=(y2-y1)/(x2-x1)
=(9-6)/(2-0)
=3/2
Do you want 19 and 20 too?
Question 1:
For this case we have that by definition, the slope of a line is given by:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]
Where:
[tex](x_ {1}, y_{1}) and (x_ {2}, y_{2})[/tex]are two points through which the line passes.
[tex](x_ {1}, y_{1}) = (- 3, -2)\\(x_ {2}, y_{2}) = (4, -1)[/tex]
Substituting in the equation:
[tex]m = \frac {-1 - (- 2)} {4 - (- 3)} = \frac {-1 + 2} {4 + 3} = \frac {1} {7}[/tex]
ANswer:
Option C
Question 2:
For this case we have that by definition, the slope of a line is given by:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]
Where:
[tex](x_ {1}, y_{1}) and (x_ {2}, y_{2})[/tex] are two points through which the line passes.
[tex](x_ {1}, y_{1}) = (0,6)\\(x_ {2}, y_{2}) = (2,9)[/tex]
Substituting in the equation:[tex]m = \frac {9-6} {2-0} = \frac {3} {2}[/tex]
ANswer:
Option A
Question 3:
For this case we have that by definition, the slope of a line is given by the following formula:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]
Where:
[tex](x_ {1}, y_{1}) and (x_ {2}, y_{2})[/tex]are two points through which the line passes.
We have as data:
[tex]m = \frac {7} {8}\\(x_ {1}, y_{1}) = (- 2,1)[/tex]
Substituting in the formula:
[tex]\frac {7} {8} = \frac {y_ {2} -1} {x_ {2} - (- 2)}\\\frac {7} {8} = \frac {y_ {2} -1} {x_ {2} +2}[/tex]
We substitute each of the points and see if the equality is met:
Point A: (6,8)
[tex]\frac {7} {8} = \frac {8-1} {6 + 2}\\\frac {7} {8} = \frac {7} {8}[/tex]
Equality is met.
Answer:
Option A
Question 4:
For this case we have that by definition, the slope of a line is given by the following formula:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}[/tex]
Where:
[tex](x_ {1}, y_{1}) and (x_ {2}, y_{2})[/tex]are two points through which the line passes.
We have as data:
[tex]m = \frac {1} {6}\\(x_ {1}, y_{1}) = (0, -3)[/tex]
Substituting in the formula:
[tex]\frac {1} {6} = \frac {y_ {2} - (- 3)} {x_ {2} -0}\\\frac {1} {6} = \frac {y_ {2} +3} {x_ {2} -0}[/tex]
We substitute each of the points and see if the equality is met:
Point A: (-3,0)
[tex]\frac {1} {6} = \frac {0 + 3} {- 3-0}\\\frac {1} {6} = \frac {3} {- 3}[/tex]
It is not fulfilled!
Point B: (6, -2)
[tex]\frac {1} {6} = \frac {-2 + 3} {6-0}\\\frac {1} {6} = \frac {1} {6}[/tex]
Equality is met!
ANswer:
Option B
