A chess club has 500 members but is losing 30 members each year. A computer club has 150 members and is gaining 20 members per year. Write and solve an equation to find the number of years it will take for the two clubs to have the same number of members.

Well for this a t-chart type of graph would help but here's how you can do it:

key: ChC = chess club
CmC = computer club

ChC = 500 members ChC = losing 30/yr
CmC = 150 members CmC = gaining 20/yr

year 1 : ChC CmC
members: 470 / 170

or.... you can scrap that, here's the simpler version :
500 - 30x = 150 +20x

solution: x = 7

Hope this helps!

Answer Link

aachen aachen · Answer 2 · 2019-09-24T01:49:16+02:00

Answer:

7 years

Step-by-step explanation:

Given: A chess club has 500 members but is losing 30 members each year. A computer club has 150 members and is gaining 20 members per year

To Find: Write and solve an equation to find the number of years it will take for the two clubs to have the same number of members

Solution:

Total members in chess club= 500

chess club loosing members each year = 30

Number of members in chess club in year [tex]\text{x}[/tex]

[tex]500-30\text{x}[/tex]

Total members in Computer club= 150

chess club gaining members each year = 20

Number of members in chess club in year [tex]\text{x}[/tex]

[tex]150+20\text{x}[/tex]

Now,

When chess club and computer club have equal number of members

[tex]500-30\text{x}[/tex]= [tex]150+20\text{x}[/tex]

[tex]500-150=30\text{x}+20\text{x}[/tex]

[tex]350=50\text{x}[/tex]

[tex]\text{x}=7[/tex]

So,

It will take 7 years for two clubs to have the same number of members.