Respuesta :
Answer: 0.068
Step-by-step explanation:
Let we denote event A for choosing a left-handed player and event B for choosing a baseball player.
Given : The probability that a randomly chosen person is a left-handed baseball player : [tex]P(A\cap B)=0.017[/tex]
The conditional probability that a randomly chosen baseball player is left-handed :
[tex]P(A|B)=0.250[/tex]
Using the formula for conditional probability:-
[tex]P(A|B)=\dfrac{P(A\cap B)}{P(B)}\\\\\Rightarrow\ P(B)=\dfrac{P(A\cap B)}{P(A|B)}[/tex]
i.e. the probability, , that a randomly chosen person from this country plays baseball will be :
[tex]P(B)=\dfrac{0.017}{0.250}=0.068[/tex]
Hence, the required probability : 0.068
The probability that a randomly chosen person from this country plays baseball is 0.068.
Given that in a particular country, the probability that a randomly chosen person is a left-handed baseball player is 0.017 and the probability that a randomly chosen baseball player is left-handed is 0.250, to determine, based on these probabilities, the probability that a randomly chosen person from this country plays baseball the following calculation must be performed:
Given that 0.250, that is, 25% of the country's baseball players are left-handed, we can say that 1/4 of the players have this ability.
So, given that 1/4 of the players represent a probability of 0.017, to determine the probability that a randomly chosen person from this country plays baseball, the following cross multiplication must be considered:
- 25 = 0.017
- 100 = X
- 100 x 0.017 / 25 = X
- 1.7 / 25 = X
- 0.068 = X
Therefore, the probability that a randomly chosen person from this country plays baseball is 0.068.
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