Suppose the population of a town is 127,000 in 2014. The population increases at a rate of 5.2 percent every year. What will the population of the town be in 2020? Round your answer to the nearest whole number.

Respuesta :

Answer:

172,146

Step-by-step explanation:

you can use the exponential growth formula and get y=127000(1.052)^6. after that, you can just solve (make sure you use PEMDAS) and get 172,146.

The population in 2020 will be 177800.

What is population growth rate definition?

The annual average rate of change of population size, for a given country, territory, or geographic area, during a specified period.

Population growth rate formula

[tex]P = P^{'} (1+i)^{n}[/tex]

where,

P is the future population size

[tex]P^{'}[/tex] is the initial population size

[tex]i[/tex] is the growth rate

n is number of periods, such as years

According to the given question

we have

Initial population = 127000

[tex]i[/tex] = 5.2% = [tex]\frac{5.2}{100} = 0.052[/tex]

n = 6 years   (2020-2014 = 6years)

therefore,

population of the town in 2020 = 127000[tex](1+0.052)^{6}[/tex]

Population of town in 2020 =  127000×[tex](1.052)^{6}[/tex]

Population of town in 2020 =  127000 ×1.4

Population of town in 2020 = 177,800

Hence, the population of town in 2020 will be 177800.

Learn more about the population growth rate here:

https://brainly.com/question/14122627

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