Create an equivalent system of equations using the sum of the system and the first equation
-3x + y = 12
x + 3y = 6

A.-3x + y = 12
- 2x + 4y = 18

B.-3x+y=12
-3x + 4y = 18

C -3x+y = 12
X + 4y = 18

D.-3x+y=12
-2x + 4y = 6​

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Answer:

[tex]\large\boxed{A.\ \left\{\begin{array}{ccc}-3x+y=12\\-2x+4y=18\end{array}\right}[/tex]

Step-by-step explanation:

[tex]\underline{+\left\{\begin{array}{ccc}-3x+y=12\\x+3y=6\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-2x+4y=18\\\\\text{therefore}\\\\\left\{\begin{array}{ccc}-3x+y=12\\-2x+4y=18\end{array}\right[/tex]

Using the equation of the sum of the system of equations and the first equation of the system, the equivalent system of equations is:

-3x + y = 12

-2x + 4y = 18

(Option A)

Given the system of equations:

  • -3x + y = 12 ---> Eqn. 1
  • x + 3y = 6 ---> Eqn. 2

Add Eqn. 1 and Eqn. 2 together:

-3x + y = 12

x + 3y = 6 (ADD)

-2x + 4y = 18

Therefore, using the equation of the sum of the system of equations and the first equation of the system, the equivalent system of equations is:

-3x + y = 12

-2x + 4y = 18

(Option A)

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