Respuesta :
Answer:
[tex]\large\boxed{A.\ \left\{\begin{array}{ccc}-3x+y=12\\-2x+4y=18\end{array}\right}[/tex]
Step-by-step explanation:
[tex]\underline{+\left\{\begin{array}{ccc}-3x+y=12\\x+3y=6\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-2x+4y=18\\\\\text{therefore}\\\\\left\{\begin{array}{ccc}-3x+y=12\\-2x+4y=18\end{array}\right[/tex]
Using the equation of the sum of the system of equations and the first equation of the system, the equivalent system of equations is:
-3x + y = 12
-2x + 4y = 18
(Option A)
Given the system of equations:
- -3x + y = 12 ---> Eqn. 1
- x + 3y = 6 ---> Eqn. 2
Add Eqn. 1 and Eqn. 2 together:
-3x + y = 12
x + 3y = 6 (ADD)
-2x + 4y = 18
Therefore, using the equation of the sum of the system of equations and the first equation of the system, the equivalent system of equations is:
-3x + y = 12
-2x + 4y = 18
(Option A)
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