Answer: 0.0336
Step-by-step explanation:
Given : The distribution of cholesterol levels in teenage boys is approximately normal with mean :[tex]\mu= 170[/tex]
Standard deviation : [tex]\sigma= 30[/tex]
The formula for z-score is given by :-
[tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For x=225
[tex]z=\dfrac{225-170}{30}=1.83[/tex]
The p-value =[tex]P(z>1.83)=1-P(z<1.83)[/tex]
[tex]=1-0.966375=0.033625\approx0.0336[/tex]
The probability that a teenage boy has a cholesterol level greater than 225 =0.0336
