Answer : The pressure of the liquid at depth of 48 ft below the surface of fluid is, 21 psi.
Explanation : Given,
The pressure of the liquid at depth 8 ft = 3.5 psi
Now we have to calculate the pressure of the liquid at depth 28 ft.
According to the question,
As, the depth of 8 ft below the surface of a stagnant fluid has pressure = 3.5 psi
So, the depth of 48 ft below the surface of a stagnant fluid has pressure = [tex]\frac{3.5\text{ psi}}{8\text{ ft}}\times 48\text{ ft}=21\text{ psi}[/tex]
Therefore, the pressure of the liquid at depth of 48 ft below the surface of fluid is, 21 psi.
