Answer:
The temperature of hot reservoir is 669.24 K.
Explanation:
It is given that,
Efficiency of gasoline engine, [tex]\eta=35.3\%=0.353[/tex]
Temperature of cold reservoir, [tex]T_C=160^{\circ}C=433\ K[/tex]
We need to find the temperature of hot reservoir. The efficiency of Carnot engine is given by :
[tex]\eta=1-\dfrac{T_C}{T_H}[/tex]
[tex]T_H=\dfrac{T_C}{1-\eta}[/tex]
[tex]T_H=\dfrac{433}{1-0.353}[/tex]
[tex]T_H=669.24\ K[/tex]
So, the temperature of hot reservoir is 669.24 K. Hence, this is the required solution.
