A vector in the xy plane has a magnitude of 25 m and x component of 12 m. What is its angle with the positive x axis?

Respuesta :

Answer:

The angle with the positive x axis 61.31°

Explanation:

It is given that, a vector in the x-y plane has a magnitude of 25 m and x component of 12 m.

x component of the vector, base = 12 m

Magnitude of hypotenuse, H = 25 m

We need to find the angle with the positive x axis. Let it is given by θ such that :

[tex]cos\theta=\dfrac{base}{hypotenuse}[/tex]

[tex]cos\theta=\dfrac{12}{25}[/tex]

θ = 61.31°

So, the angle with the positive x axis 61.31°. Hence, this is the required solution.