Answer:
Option C is the correct answer.
Explanation:
We have ideal gas equation, PV = nRT
Volume of tank, V = 1 m³
Mass of water = 10 kg
Mass of 1 mole of water = 18 g = 0.018 kg
Number of moles,
[tex]n=\frac{10}{0.018}=555.56moles[/tex]
Temperature, T = 160 °C = 160 + 273 = 433 K
Ideal gas constant, R = 8.314 JK⁻¹mol⁻¹
Substituting
P x 1 = 555 x 8.314 x 433
P = 2000000 Pa = 2000 kPa
The pressure in the tank is 2000 kPa
Option C is the correct answer.