Explanation:
a) The equivalent resistance for resistors in series is the sum:
R = R₁ + R₂ + R₃
R = 10 Ω + 20 Ω + 30 Ω
R = 60 Ω
b) The resistors are in series, so they have the same current.
I = V/R
I = 12 V / 60 Ω
I = 0.2 A
c) The voltage drop can be found with Ohm's law:
V₁ = I R₁ = (0.2 A) (10 Ω) = 2 V
V₂ = I R₂ = (0.2 A) (20 Ω) = 4 V
V₃ = I R₃ = (0.2 A) (30 Ω) = 6 V
d) The power lost in each resistor is current times voltage drop:
P₁ = I V₁ = (0.2 A) (2 V) = 0.4 W
P₂ = I V₂ = (0.2 A) (4 V) = 0.8 W
P₃ = I V₃ = (0.2 A) (6 V) = 1.2 W
(a) The equivalent resistance of the circuit is 60 Ω.
(b) The current in each resistor is 0.2 A.
(c) The voltage across each resistor is 2 V, 4 V, and 6 V respectively.
(d) The power lost in each resistor is 0.4 W, 0.8 W and 1.2 W.
The equivalent resistance of the circuit is determined as follows;
Rt = R₁ + R₂ + R₃
Rt = 10 + 20 + 30
Rt = 60 Ω
The current in the resistors is calculated as follows;
V = IR
I = V/R
I = 12/60
I = 0.2 A
V1 =IR1 = 0.2 x 10 = 2 V
V2 = IR2 = 0.2 x 20 = 4 V
V3 = 0.2 x 30 = 6 V
P1 = I²R1 = (0.2)² x 10 = 0.4 W
P2 = I²R2 = (0.2)² x 20 = 0.8 W
P3 = I²R3 = (0.2)² x 30 = 1.2 W
Learn more about series circuit here:https://brainly.com/question/19865219
