The point-slope form of the equation of the line that passes through (-4, -3) and (12,1) is y-1=1/4(×-12). What is the standard form of the equation for this line?

Respuesta :

Answer:

x - 4y = 8

Step-by-step explanation:

We are given point slope form of the equation of the line that passes through the point [tex](-4, -3)[/tex] and [tex](12,1)[/tex] which is [tex]y-1=\frac{1}{4} (x-12)[/tex].

We are to write this equation in its standard form.

From the given equation, we know that the slope is [tex]\frac{1}{4}[/tex] so we will find the y intercept.

[tex]y=mx+c[/tex]

[tex]1=\frac{1}{4}\times (12) +c[/tex]

[tex]c=-2[/tex]

Substituting the given values and the y intercept in the standard form of equation.

[tex]y=mx+c[/tex]

[tex]y=\frac{1}{4} x-2[/tex]

Rearranging this to get:

x - 4y = 8

Answer:

x - 4y = 8.

Step-by-step explanation:

y - 1 = 1/4(x - 12)

y = 1/4x - 3 + 1

y = 1/4x - 2

1/4x - y - 2 = 0

1/4x - y = 2

Multiply through by 4:

x - 4y = 8 is standard form.