Respuesta :

Answer:

Correct Answer :

(27/2, 3/2)

Step-by-step explanation:

The centre of the circumscribing the quadrilateral whose sides are 3x+y=22, x-3y=14 and 3x+ y=62 is

A.  (3/2, 27/2)

B.  (27/2, 3/2)

C.  (27, 3)

D.  (1, 2/3)

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If [(3x+4)/(x2-3x+2)]=[A/(x-2)]+[B/(x-1)] then (A,B)=

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1+[(1/2).(3/5)]+[(1.3/2.4)(3/5)2]+[(1.3.5/2.4.6)(3/5)3]+-------∞=