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Write an equation of the horizontal asymptote for this function. Also, interpret what this asymptote means in the context of the problem (in terms of the fish population and the number of years since the fish were introduced into the lake.)

Write an equation of the horizontal asymptote for this function Also interpret what this asymptote means in the context of the problem in terms of the fish popu class=

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Cxlver

Answer:

Step-by-step explanation:

First, finding the horizontal asymptote:

[tex]\lim_{t \to \infty} = \frac{200+40t}{1+0.05t} = \frac{\frac{200}{t} 40 }{\frac{1}{t} 0.05} = 800[/tex]

In the context of the problem, the horizontal asymptote speaks about where the population of the fish is headed and capped.

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