The question asks, "Find the equation of the ellipse with the following properties.

The ellipse with x-intercepts (5, 0) and (-5, 0); y-intercepts (0, 3) and (0, -3)."
I know that the equation for an ellipse is x^2/a^2+ y^2/b^2=1 but I have no idea how to create the equation given x-intercepts and y-intercepts. Please help! Thank you.


Respuesta :

Answer:

x^2 / 25 + y^2 / 9 = 1

Step-by-step explanation:

The major axis is along the x axis and the minor axis is on the y axis.

Major axis = 2a =  5--5 =10 so a = 5 and a^2 = 25.

Similarly b^2 = 3^2 = 9.

Answer:

[tex]\frac{x^2}{25}+\frac{y^2}{9}=1[/tex]

Step-by-step explanation:

Equation of ellipse is of form [tex]\frac{x^2}{a^2}+\frac{y^2}{b^2}=1[/tex] where [tex](a,0) , (-a,0)[/tex] are the x-intercepts and [tex](0,b) , (0,-b)[/tex] are the y-intercepts . If [tex]a > b[/tex] then it is a horizontal ellipse and if [tex]a < b[/tex] then it is a vertical ellipse .

For horizontal axis ,

Here, [tex](a,0) , (-a,0)[/tex] are known as the vertices of ellipse and [tex](0,b) , (0,-b)[/tex] are the co-vertices of ellipse .

Horizontal axis is known as the major axis and vertical axis is known as the minor axis .

Here, x-intercepts are [tex](5,0) , (-5,0)[/tex] , take a = 5

y-intercepts are [tex](0,3) , (0,-3)[/tex] , take b = 3

As [tex]a > b[/tex] , it is a horizontal ellipse .

On putting a = 5 and b = 3 , we get equation as

[tex]\frac{x^2}{5^2}+\frac{y^2}{3^2} =1\\ \frac{x^2}{25}+\frac{y^2}{9} =1[/tex]