Answer:
The object's maximum speed remains unchanged.
Explanation:
The speed of a particle in SHM is given by :
[tex]v(t)=A\omega\ sin(\omega t)[/tex]
Maximum speed is, [tex]v_{max}=A\omega[/tex]
If A' = 2A and T' = 2T
[tex]v'_{max}=(2A)\dfrac{2\pi}{2T}[/tex]
[tex]v'_{max}=(A)\dfrac{2\pi}{T}[/tex]
[tex]v'_{max}=v_{max}[/tex]
So, the maximum speed of the object remains the same i.e. it remains unchanged. Hence, this is the required solution.
