Answer:
a. 76.92 MW
b. 26.92 MW
Explanation:
η = Efficiency of the power plant = 0.35
Q₂ = rate at which heat rejected to surrounding = 50 MW
Q₁ = Rate of Input heat = ?
Efficiency of the power plant is given as
[tex]\eta =1-\frac{Q_{2}}{Q_{1}}[/tex]
[tex]0.35 =1-\frac{50}{Q_{1}}[/tex]
Q₁ = 76.92 MW
Net Rate of work is given as
Q = Q₁ - Q₂
Q = 76.92 - 50
Q = 26.92 MW
