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A plastic rod that has been charged to â14 nC touches a metal sphere. Afterward, the rod's charge is â1.0 nC . How many charged particles were transferred?
Express your answer using two significant figures.

Respuesta :

Answer:

[tex]N = 8.1 \times 10^{10}[/tex]

Explanation:

Initial charge on the rod is

[tex]Q_i = 14 nC[/tex]

final charge on the rod is

[tex]Q_f = 1 nC[/tex]

now the charge transferred from to the sphere is given as

[tex]\Delta Q = Q_i - Q_f[/tex]

[tex]\Delta Q = 14 - 1 = 13 nC[/tex]

now we also know that

Q = Ne

so number of particles transferred is

[tex]N = \frac{\Delta Q}{e}[/tex]

[tex]N = \frac{13 \times 10^{-9}}{1.6 \times 10^{-19}}[/tex]

[tex]N = 8.1 \times 10^{10}[/tex]

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