Answer:
Displacement is 565.69 m at 45° west of north
Explanation:
Let north represent positive y axis and east represent positive x axis.
We have journey started from 600 N. Michigan Avenue, and walked 3 blocks toward north, 4 blocks toward west, and 1 block toward north to a train station.
3 blocks toward north = 300 j m
4 blocks toward west = -400 i m
1 blocks toward north = 100 j m
Total displacement = -400 i + 400 j m
Magnitude
[tex]s=\sqrt{(-400)^2+400^2}=565.69m[/tex]
Direction,
[tex]\theta =tan^{-1}\left ( \frac{400}{-400}\right )=135^0[/tex]
Direction is 45° west of north.
Displacement is 565.69 m at 45° west of north
