Answer:
The intensity of sound (I) = 3.16 x 10⁻⁶ W/m²
Explanation:
We have expression for sound intensity level (SIL),
[tex]L=10log_{10}\left ( \frac{I}{I_0}\right )[/tex]
Here we need to find the intensity of sound (I).
[tex]L=10log_{10}\left ( \frac{I}{I_0}\right )\\\\log_{10}\left ( \frac{I}{I_0}\right )=0.1L\\\\\frac{I}{I_0}=10^{0.1L}\\\\I=I_010^{0.1L}[/tex]
Substituting
L = 67 dB and I₀ = 10⁻¹² W/m² in the equation
[tex]I=I_010^{0.1L}=10^{-12}\times 10^{0.1\times 65}\\\\I_0=10^{-12}\times 10^{6.5}=10^{-5.5}=3.16\times 10^{-6}W/m^2[/tex]
The intensity of sound (I) = 3.16 x 10⁻⁶ W/m²
