Answer:
[tex]H^+ = 8.482 * 10^-5[/tex]M
Step-by-step explanation:
Given
[tex]E = 0.52\\E^o= 0.76\\[/tex]
As per the Faraday's law,
[tex]E = E^o - \frac{RT}{nF} lnQ\\[/tex]
Where E is the Cell Potential
[tex]E^o[/tex] is the standard cell potential
n is the number of moles
F is the Faraday's constant
T is the standard temperature
Q [tex]= \frac{1}{(H^+)^2}[/tex]
Substituting the given values in above equation, we get -
[tex]0.52 = 0.76 - \frac{(8.314*298)}{(2*96485)}ln\frac{1}{(H+)^2} \\0.24 = 0.0128 ln\frac{1}{(H^+)^2}\\ln\frac{1}{(H^+)^2} = 18.75\\\frac{1}{(H^+)^2} = 139002155.8\\H^+ = 8.482 * 10^-5[/tex]M
