Answer:
E = 4.9735 × 10⁸ J
Explanation:
Given:
Charge transferred, q = 46.7 C
Potential difference, ΔV = 10.65 MV = 10.65 × 10⁶ V
Now, the relation between the energy (E) , charge (q) and the potential difference is given as:
E = qΔV
on substituting the values in the above equation, we get
E = 46.7 × 10.65 × 10⁶ V
or
E = 4.9735 × 10⁸ J
Hence, the energy released is 4.9735 × 10⁸ J