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A ball is released at a height of 16 inches to roll inside a half-cylinder. It rolls
to a height of 8 inches on the other side of the cylinder on roll 1. Each time it
rolls up a side of the cylinder, the ball reaches a point that is 1/2 as high as it
had reached on the other side.
This explicit formula models the height of the ball, in inches, the nth time it
rolls up a side of the cylinder.
an=8*(1/2) ^(n-1)
How high does the ball roll on its 5th time up the cylinder's side?

Respuesta :

znk

Answer:

[tex]\boxed{\dfrac{1}{2} \text{ in}}[/tex]

Step-by-step explanation:

aₙ = 8(½)ⁿ⁻¹

If n = 5

 a₅ = 8(½)⁵⁻¹

 a₄ = 8(½)⁴ = 8 × ¹/₁₆ = ½ in

[tex]\text{On its fifth time, the ball will roll $\boxed{\mathbf{\dfrac{1}{2} in}}$ up the cylinder's side}[/tex]

Answer: 1/2 inch

Step-by-step explanation: Letter d

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