Answers:
extra work required = 0.038 J
Explanation:
let X = 13.3 cm and Y = 13.4 cm, W1 be the work done to stretch the spring 13.3 cm and W2 be the work done to stretch the spring 13.4cm .let F be the force stretching the spring.
from Work and Energy principles:
W1 = F×X×cos(Ф) = F×X , since the force is acting in the direction at which the spring is stretching , cos(Ф) = 1
then :
W1 = F×X
F = W1/X
= 5.06/(13.3×10^-2)
= 38.05 J
and,
W2 = F×Y×cos(Ф) = F×Y , ince the force is acting in the direction at which the spring is stretching , cos(Ф) = 1
W2 = F×Y
= (38.5)×(13.4×10^*2)
= 5.098 J
therefore, the extra required is 5.098 - 5.06 = 0.038 J.
