contestada

A conducting coil of 1750 turns is connected to a galvanometer, and the total resistance of the circuit is 30 Ω. The area of each turn is 5.00 × 10^-4 m2. This coil is moved from a region where the magnetic field is zero into a region where it is nonzero, the normal to the coil being kept parallel to the magnetic field. The amount of charge that is induced to flow around the circuit is measured to be 9.0 × 10^-3 C. Find the magnitude of the magnetic field

Respuesta :

Answer:

0.31 T

Explanation:

N = 1750

R = 30 ohm

A = 5 x 10^-4 m^2

B1 = 0 T

q = 9 x 10^-3 C

Let the magnetic field is B ad the time is t.

B2 = B

Use the Faraday's law of electromagnetic induction

e = dФ / dt

i R = N x A x (B2 - B1) / t

i x R / t = N x A x B

q x R = N x A x B

9 x 10^-3 x 30 = 1750 x 5 x 10^-4 x B

B = 0.31 T

Otras preguntas