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A baseball player hit 60 home runs in a season. Of the 60 home runs, 19 went to right field, 20 went to right center field, 9 went to center field, 10 went to left center field, and 2 went to left field.
(a) What is the probability that a randomly selected home run was hit to right field?
(b) What is the probability that a randomly selected home run was hit to left field?
(c) Was it unusual for this player to hit a home run to left field? Explain.

Respuesta :

Answer:

a)[tex]P(E_{1})=\frac{19}{60}[/tex]

b)[tex]P(E_{2})=\frac{2}{60}=\frac{1}{30}[/tex]

Step-by-step explanation:

PROBABILITY OF AN EVENT IS DEFINED AS

[tex]P(E)=\frac{FavourableCases}{TotalCases}[/tex]

a)

Favorable cases for runs being scored on right of field are 19 Thus probability equals

[tex]P(E_{1})=\frac{19}{60}[/tex]

b)

Favorable cases for runs being scored on left of field are 2 Thus probability equals

[tex]P(E_{2})=\frac{2}{60}=\frac{1}{30}[/tex]

c)

Yes it was unusual for the player to hit a home run to left of the field since his probability of hitting the run towards his left is least among all the other areas in which he scored runs.