If a football player passes a football from 4 feet off the ground with an initial velocity of 36 feet per second, how long will it take the football to hit the ground? Use the equation h = −16t^2 + 6t + 4. Round your answer to the nearest hundredth.
A) 0.72
B) 0.65
C) 0.35
D) 0.27

Respuesta :

Answer:

Option A is correct

Step-by-step explanation:

The given equation is

h = -16t^2+6t+4

When the ball will hit the ground, height h = 0

Putting value of h = 0

0 = -16t^2+6t+4

Now solving to find the value of t

=> -16t^2+6t+4 = 0

Multiply with -1

16t^2-6t-4=0

Using quadratic formula to find value of t

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

a= 16, b= -6 and c= -4

Putting values,

[tex]t=\frac{-(-6)\pm\sqrt{(-6)^2-4(16)(-4)}}{2(16)}\\t=\frac{6\pm\sqrt{36+256}}{32}\\t=\frac{6\pm\sqrt{292}}{32}\\t=\frac{6\pm17.08}{32}\\t=\frac{6+17.08}{32} \,\,and\,\, t=\frac{6-17.08}{32}\\t=0.721\,\,and\,\, t=-0.34[/tex]

Since time cannot be negative, so t = 0.721 or 0.72

So, Option A is correct