Answer:
a. 2.5%
Step-by-step explanation:
The Z-score of the given test score is ...
Z = (X -μ)/σ = (700 -500)/100 = 2
The empirical rule tells you 95% of a normal distribution is within 2σ of the mean. The other 5% is split evenly between the two tails of the distribution, so the probability of a score 2σ or more above the mean is about 1/2×5% = 2.5%.