Answer: There are 99 three-legged-cows and 28 chickens.
Step-by-step explanation:
Let x be the number of three-legged-cows and y be the number of chickens.
Number of legs in chicken = 2
The according to the question, we have the following equations :-
[tex]\text{For heads }x+y=127------(1)\\\\\text{For legs }3x+2y=353------(2)[/tex]
Multiplying 2 to the equation (1), we get
[tex]2x+2y=254--------(3)[/tex]
Now, subtract equation (3) from (2), we get
[tex]x=353-254=99[/tex]
Put x= 99 in (1), we get
[tex]99+y=127\\\\\Rightarrow\ y=127-99=28[/tex]
Hence, there are 99 three-legged-cows and 28 chickens.
