Answer:
The magnetic field strength inside the solenoid is [tex]5.026\times10^{-3}\ T[/tex].
Explanation:
Given that,
Radius = 2.0 mm
Length = 5.0 cm
Current = 2.0 A
Number of turns = 100
(a). We need to calculate the magnetic field strength inside the solenoid
Using formula of the magnetic field strength
Using Ampere's Law
[tex]B=\dfrac{\mu_{0}NI}{l}[/tex]
Where, N = Number of turns
I = current
l = length
Put the value into the formula
[tex]B=\dfrac{4\pi\times10^{-7}\times100\times2.0}{5.0\times10^{-2}}[/tex]
[tex]B=0.005026=5.026\times10^{-3}\ T[/tex]
(b). We draw the diagram
Hence, The magnetic field strength inside the solenoid is [tex]5.026\times10^{-3}\ T[/tex].
