In some Rutherford scattering experiments, the alpha particles had kinetic energies of 9.3 MeV . What’s the speed of such an alpha particle?

Respuesta :

Answer:

Speed of an alpha particle is, [tex]v=2.11\times 10^7\ m/s[/tex]

Explanation:

It is given that,

Kinetic energy of the alpha particles, [tex]E=9.3\ MeV=9.3\times 10^6\ eV[/tex]

Since, [tex]1\ eV=1.6\times 10^{-19}\ J[/tex]

Kinetic energy, [tex]E=1.48\times 10^{-12}\ J[/tex]

We need to find the speed of alpha particle. The kinetic energy os given by :

[tex]E=\dfrac{1}{2}mv^2[/tex]

m is the mass of alpha particle, [tex]m=6.64\times 10^{-27}\ kg[/tex]

[tex]v=\sqrt{\dfrac{2E}{m}}[/tex]

[tex]v=\sqrt{\dfrac{2\times 1.48\times 10^{-12}}{6.64\times 10^{-27}}}[/tex]

v = 21113576.97 m/s

or

[tex]v=2.11\times 10^7\ m/s[/tex]

So, the speed of such an alpha particle is [tex]2.11\times 10^7\ m/s[/tex]. Hence, this is the required solution.