Answer:
42.11 sec
Explanation:
In first part : The truck start from the rest that is u = 0 m/sec
Acceleration is given as [tex]a=1.4m/sec^2[/tex]
It reaches to a velocity of 22 m/sec so v=22 m/sec
Now according to first law of motion [tex]v=u+at[/tex]
[tex]22=0+1.4\times t[/tex]
[tex]t=15.71sec[/tex]
In second part : The truck maintain a constant speed for 22 sec
In third part : The truck takes an additional 4.4 sec for stopping
So total time in which the truck is in motion =15.71+22+4.4=42.11 sec