Answer:
178 torr
Explanation:
Using Ideal gas equation for same mole of gas as
[tex] \frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}[/tex]
Given ,
V₁ = 5 mL
V₂ = 5 mL (Closed container)
P₁ = 95.0 torr
P₂ = ?
T₁ = 28.0 ºC
T₂ = 290 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (28 + 273.15) K = 301.15 K
T₂ = (290 + 273.15) K = 563.15 K
Using above equation as:
[tex] \frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}[/tex]
[tex] \frac {{95.0}\times {5}}{301.15}=\frac {{P_2}\times {5}}{563.15}[/tex]
Solving for V₂ , we get:
P₂ = 178 torr
