Answer:
162g per mol of octane
Explanation:
The combustion reaction of octane is:
2C8H18 + 25O2 ⇒ 16CO2 + 18H2O
That means the reaction produces 18mol of water per 2 mol of octane burned, so if we burn 1 mol of octane we can obtain the mass of water like this:
[tex]1molC8H18x\frac{18molH2O}{2molC8H18} x\frac{18gH2O}{1molH2O} = 162g [/tex] of water per mol of C8H18 burned